Torque (article) | Khan Academy (2024)

Learn how to find the torque exerted by a force.

What is torque?

Torque is a measure of the force that can cause an object to rotate about an axis. Just as force is what causes an object to accelerate in linear kinematics, torque is what causes an object to acquire angular acceleration.

Torque is a vector quantity. The direction of the torque vector depends on the direction of the force on the axis.

Anyone who has ever opened a door has an intuitive understanding of torque. When a person opens a door, they push on the side of the door farthest from the hinges. Pushing on the side closest to the hinges requires considerably more force. Although the work done is the same in both cases (the larger force would be applied over a smaller distance) people generally prefer to apply less force, hence the usual location of the door handle.

Torque can be either static or dynamic.

A static torque is one which does not produce an angular acceleration. Someone pushing on a closed door is applying a static torque to the door because the door is not rotating about its hinges, despite the force applied. Someone pedaling a bicycle at constant speed is also applying a static torque because they are not accelerating.

The drive shaft in a racing car accelerating from the start line is carrying a dynamic torque because it must be producing an angular acceleration of the wheels given that the car is accelerating along the track.

The terminology used when describing torque can be confusing. Engineers sometimes use the term moment, or moment of force interchangeably with torque. The radius at which the force acts is sometimes called the moment arm.

How is torque calculated?

The magnitude of the torque vector $τ$ ‍ for a torque produced by a given force $F$ ‍ is

$τ = F \cdot r \sin (θ)$ ‍

where $r$ ‍ is the length of the moment arm and $θ$ ‍ is the angle between the force vector and the moment arm. In the case of the door shown in Figure 1, the force is at right angles (90 $^{\circ}$ ‍) to the moment arm, so the sine term becomes 1 and

$τ = F \cdot r$ ‍.

The direction of the torque vector is found by convention using the right hand grip rule. If a hand is curled around the axis of rotation with the fingers pointing in the direction of the force, then the torque vector points in the direction of the thumb as shown in Figure 2.

The direction of the torque vector embeds two pieces of information that describe the torque.

The plane in which the object is (or could be) rotating. This is not arbitrary.
The direction of rotation (clockwise or counterclockwise). This can in principle be defined differently depending on the location of the observer.

One way of describing a plane in three dimensions is with a vector perpendicular to the plane as shown in Figure 3. This is called the point normal form. The torque vector is the normal vector to the plane of rotation.

The use of the right-hand rule (as opposed to a left hand rule) is by convention. However, this convention is followed consistently in physics. Doing so allows us to use the framework of vector mechanics in problems such as those involving angular momentum.

How is torque measured?

The SI unit for torque is the Newton-meter.

In imperial units, the Foot-pound is often used. This is confusing because colloquially the pound is sometimes used as a unit of mass and sometimes force. What is meant here is pound-force, the force due to earth gravity on a one-pound object. The magnitude of these units is often similar as $1 Nm ≃ 1.74 ft \cdot lbs$ ‍.

Measuring a static torque in a non-rotating system is usually quite easy, and done by measuring a force. Given the length of the moment arm, the torque can be found directly. Measuring torque in a rotating system is considerably more difficult. One method works by measuring strain within the metal of a drive shaft which is transmitting torque and sending this information wirelessly.

What role does torque play in rotational kinematics?

In rotational kinematics, torque takes the place of force in linear kinematics. There is a direct equivalent to Newton’s 2ⁿᵈ law of motion ( $F = m a$ ‍),

$τ = I α$ ‍.

Here, $α$ ‍ is the angular acceleration. $I$ ‍ is the rotational inertia, a property of a rotating system which depends on the mass distribution of the system. The larger $I$ ‍, the harder it is for an object to acquire angular acceleration. We derive this expression in our article on rotational inertia.

What is rotational equilibrium?

The concept of rotational equilibrium is an equivalent to Newton’s 1ˢᵗ law for a rotational system. An object which is not rotating remains not rotating unless acted on by an external torque. Similarly, an object rotating at constant angular velocity remains rotating unless acted on by an external torque.

The concept of rotational equilibrium is particularly useful in problems involving multiple torques acting on a rotatable object. In this case it is the net torque which is important. If the net torque on a rotatable object is zero then it will be in rotational equilibrium and not able to acquire angular acceleration.

Exercise 1:

Consider the wheel shown in Figure 3, acted on by two forces. What magnitude of the force $F_{2}$ ‍ will be required for the wheel to be in rotational equilibrium?

Solution:

We begin by finding the torque $τ_{1}$ ‍ due to $F_{1}$ ‍.

$\begin{aligned} τ_{1} & = F r \sin (θ) \\ = (5 N) \cdot (0.075 m) \sin (135^{\circ}) \\ ≃ + 0.265 Nm \end{aligned}$ ‍

Note that here we are defining positive torque in the direction out of the page. We know that in rotational equilibrium

$τ_{1} + τ_{2} = 0$ ‍

$τ_{2} = - F_{2} \cdot 0.1 m \cdot \sin (90^{\circ})$ ‍ and therefore $F_{2} ≃ 2.65 N$ ‍

How does torque relate to power and energy?

There is considerable confusion between torque, power and energy. For example, the torque of an engine is sometimes incorrectly described as its 'turning power'.

Torque and energy have the same dimensions (i.e. they can be written in the same fundamental units), but they are not a measure of the same thing. They differ in that torque is a vector quantity defined only for a rotatable system.

Power however, can be calculated from torque if the rotational speed is known. In fact, the horsepower of an engine is not typically measured directly, but calculated from measured torque and rotational speed. The relationship is:

$\begin{aligned} P & = \frac{Force \cdot Distance}{Time} \\ = \frac{F \cdot 2 π r}{t} \\ = 2 π τ ω (ω in revolutions / \sec) \\ = τ ω (ω in radian / \sec) \end{aligned}$ ‍

Along with horsepower, the peak torque produced by a vehicle engine is an important and commonly quoted specification. Practically speaking, peak torque is relevant for generally describing how quickly a vehicle will accelerate and its ability to pull a load. Horsepower (relative to weight) on the other hand is more relevant to the maximum speed of a vehicle.

The maximum speed of a vehicle occurs when the power developed by the engine becomes equal to the rate of work done by friction and drag. See our article on power for more detail on this.

It is important to recognize that while maximum torque and horsepower are useful general specifications, they are of limited use when making calculations involving the overall motion of a vehicle. This is because in practice both vary as a function of rotational speed. The general relationship can be non-linear and differs for different types of motor as shown in Figure 4.

In steam engines and electric motors the rate of conversion of energy from the primary source (steam from a boiler, electricity from a battery) is mostly independent of the rotational speed. In internal combustion engines the combustion pressure and temperature increase with rotational speed. An optimum combination of these variables occurs at a specific rotational speed, leading to the observed peak in available torque.

How can we increase or decrease torque?

It is often necessary to increase or decrease the torque produced by a motor to suit different applications. Recall that the length of a lever can increase or decrease the force on an object at the expense of the distance through which the lever must be pushed. Similarly, the torque produced by a motor can be increased or decreased through the use of gearing. An increase in torque comes with a proportional decrease in rotational speed. The meshing of two gear teeth can be viewed as equivalent to the interaction of a pair of levers as shown in Figure 5.

The use of adjustable gearing is necessary to obtain good performance in vehicles powered by combustion engines. These engines produce maximum torque only for a narrow range of high rotational speeds. Adjustable gearing allows sufficient torque to be delivered to the wheels at any given rotational speed of the engine.

Bicycles require gearing because of the inability of humans to pedal with a cadence sufficient to achieve a useful speed when driving a wheel directly (unless one is cycling a penny-farthing).

The old-style penny-farthing type bicycle used a large front drive wheel (up to 1.5 m diameter) driven directly by the rider. Because the tangential speed of the rim increases with radius, no gearing is required yet it is possible to attain speeds of 15-25 km/hr.

Adjustable gearing is not typically required in vehicles powered by steam engines or electric motors. In both cases, high torque is available at low speeds and is relatively constant over a wide range of speeds.

Exercise 2a:

A gasoline engine producing $150 Nm$ ‍ of torque at a rotational speed of $300 rad / s$ ‍ is used to drive a winch and lift a weight as shown in figure 6. The winch drum has a radius of 0.25 m and is driven from the engine via a 1:50 speed reduction gear. What mass could be raised with this setup? (Assume the winch is in rotational equilibrium, i.e. the mass is traveling up at constant velocity).

Solution:

If the winch is in rotational equilibrium, we know that the torque produced by the winch must equal the opposing torque due to the weight. If $R$ ‍ is the reduction ratio and $τ_{m}$ ‍ is the torque produced by the engine then the torque produced by the winch is

$τ_{w} = \frac{τ_{m}}{R}$ ‍

which can be written in terms of a force at the radius of the winch drum $r$ ‍,

$F = \frac{τ_{m}}{R r}$ ‍

so the mass being lifted is

$\begin{aligned} m & = \frac{τ_{m}}{R r g} \\ = \frac{150 Nm}{\frac{1}{50} \cdot 0.25 m \cdot 9.81 m / s^{2}} \\ ≃ 3060 kg \end{aligned}$ ‍

Exercise 2b:

At what speed would the weight be traveling upward?

Solution:

Because we know that an increase in torque due to gearing produces a proportional decrease in rotational velocity, the rotational velocity of the winch drum must be

$ω_{w} = ω_{m} R$ ‍

The velocity of the rim of the winch drum is equal to that of the mass being raised, so

$\begin{aligned} v & = r ω_{w} \\ = r ω_{m} R \\ = 0.25 m \cdot 300 rad / s \cdot \frac{1}{50} \\ ≃ 1.5 m / s \end{aligned}$ ‍

Data sources

Cyclist : Hansen, E.A, Smith G. Factors affecting cadence choice during submaximal cycling and cadence influence on performance. International Journal of Sports Physiology and Performance. March 2009; 4(1):3-17.

Diesel engine: Mercedes 250 CDI

Otto cycle engine: Mercedes E250

Electric motor: Tesla Model S 85

Steam locomotive: 2-8-0 "Consolidation" Locomotive at 70% boiler capacity

Penny-farthing : Wikimedia Commons